How can I output a list of all installed packages with installation date and additional information?

0

3 Answers

Open Terminal and run:

zgrep 'install ' /var/log/dpkg.log* | sort | cut -f1,2,4 -d' '

Example output:

2018-09-02 16:10:59 python3-psutil:amd64 2018-09-02 16:11:00 menulibre:all 2018-09-07 14:58:58 indicator-stickynotes:all 2018-09-08 00:17:41 libdumbnet1:amd64 2018-09-08 00:17:41 libxmlsec1-openssl:amd64 ...

Since this command will look up into all logs thus the output can be very big. So, it's better to save it into file using

zgrep 'install ' /var/log/dpkg.log* | sort | cut -f1,2,4 -d' ' > test.txt
5

Here is a script that uses the files /var/log/dpkg.log* to construct a list of currently installed packages together with the most recent installation date.

#!/bin/bash LOGDIR=$(mktemp -d) cd $LOGDIR cp /var/log/dpkg.log* . # grep the relevant lines from the log files for file in dpkg.log* do zgrep ' install ' "$file" > ins.${file%.gz} done # Merge all the install lines chronologically into a single file cat $(ls -rv ins.*) > install.log # Construct a list of all installed packages in the format packagename:arch dpkg -l | grep '^.i' | tr -s ' ' | cut -d' ' -f2,4 | tr ' ' : | cut -d: -f1,2 > installed.list OUTFILE=$(mktemp -p .) for package in $(< installed.list) do # Get only the most recent installation of the respective package grep " $package" install.log | tail -n1 >> "$OUTFILE" done sort "$OUTFILE" > newest-installs.log echo "List of installed packages written to ${LOGDIR}/newest-installs.log"
3

Use 

tail -f /var/log/dpkg.log

or

less /var/log/dpkg.log

or

grep " install " /var/log/dpkg.log* zgrep " install " /var/log/dpkg.log.*.gz

can use grep for a particular package (example)

grep -E 'install .*<package-name>' /var/log/dpkg.log*